.115=(x^2)+.45x

Solution for .115=(x^2)+.45x equation:

.115=(x^2)+.45x

We move all terms to the left:

.115-((x^2)+.45x)=0

We add all the numbers together, and all the variables

-(x^2+.45x)+0.115=0

We get rid of parentheses

-x^2-.45x+0.115=0

We add all the numbers together, and all the variables

-1x^2-0.45x+0.115=0

a = -1; b = -0.45; c = +0.115;
Δ = b2-4ac
Δ = -0.452-4·(-1)·0.115
Δ = 0.6625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.45)-\sqrt{0.6625}}{2*-1}=\frac{0.45-\sqrt{0.6625}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.45)+\sqrt{0.6625}}{2*-1}=\frac{0.45+\sqrt{0.6625}}{-2}
$